# MATHS SHORTCUT TRICKS FOR CBSE

## INTEGRATION SHORTCUT FOR JEE/CBSE/ISC/WBJEE…

Students,this is so simple and very easy trick to use but very very important regarding to your exam.
Let see the types of integration,

i.e ∫0^2019π[sin⁡x+cos⁡x ]dx=?
∫0^2018π[sin⁡x+cos⁡x ]dx=?
∫0^5000π[sin⁡x+cos⁡x ]dx=?
∫0^3300π[sin⁡x+cos⁡x ]dx=? { [x], denotes Greatest Integer of Function }
……..and so on.
Students,for evaluate this type Integration you have to remember a simple formula like,

## ∫0^2nπ[sin⁡x+cos⁡x ]dx=-nπ

So,according to formula ,we get of

∫0^2019π[sin⁡x+cos⁡x ]dx =-2019/2 π , so simple
From ,2nπ=2019π,
hence,n=2019/2
Now we can evaluate this type of problem in just a fraction
Hence
∫_0^5000π〖[sin⁡x+cos⁡x ]dx=-〗 2500π
∫_0^3300π〖[sin⁡x+cos⁡x ]dx=-1650π〗
∫_0^2018π[sin⁡x+cos⁡x ]dx=-1009π
THANK YOU…………